(10x+18)-[2*(3x+4)]=0

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Solution for (10x+18)-[2*(3x+4)]=0 equation:


Simplifying
(10x + 18) + -1[2(3x + 4)] = 0

Reorder the terms:
(18 + 10x) + -1[2(3x + 4)] = 0

Remove parenthesis around (18 + 10x)
18 + 10x + -1[2(3x + 4)] = 0

Reorder the terms:
18 + 10x + -1[2(4 + 3x)] = 0
18 + 10x + -1[(4 * 2 + 3x * 2)] = 0
18 + 10x + -1[(8 + 6x)] = 0
18 + 10x + [8 * -1 + 6x * -1] = 0
18 + 10x + [-8 + -6x] = 0

Reorder the terms:
18 + -8 + 10x + -6x = 0

Combine like terms: 18 + -8 = 10
10 + 10x + -6x = 0

Combine like terms: 10x + -6x = 4x
10 + 4x = 0

Solving
10 + 4x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + 4x = 0 + -10

Combine like terms: 10 + -10 = 0
0 + 4x = 0 + -10
4x = 0 + -10

Combine like terms: 0 + -10 = -10
4x = -10

Divide each side by '4'.
x = -2.5

Simplifying
x = -2.5

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